5x=12+18x2^12/20-82+104-3x+(-8x)

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Solution for 5x=12+18x2^12/20-82+104-3x+(-8x) equation: 



5x=12+18x^2^12/20-82+104-3x+(-8x)

We move all terms to the left:

5x-(12+18x^2^12/20-82+104-3x+(-8x))=0



Domain of the equation: 20-82+104-3x+(-8x))!=0

We move all terms containing x to the left, all other terms to the right

-3x+(-8x))!=-42

x∈R



We multiply all the terms by the denominator


-(12+18x^2^12+5x*20-82+104-3x+(-8x))=0



We calculate terms in parentheses: -(12+18x^2^12+5x*20-82+104-3x+(-8x)), so:

12+18x^2^12+5x*20-82+104-3x+(-8x)

determiningTheFunctionDomain
18x^2^12+5x*20-3x+(-8x)+12-82+104

We add all the numbers together, and all the variables

18x^2^12-3x+5x*20+(-8x)+34

Wy multiply elements

18x^2^12-3x+100x+(-8x)+34

We get rid of parentheses

18x^2^12-3x+100x-8x+34

We add all the numbers together, and all the variables

18x^2^12+89x+34

Back to the equation:

-(18x^2^12+89x+34)



We get rid of parentheses

-18x^2^12-89x-34=0

We move all terms containing x to the left, all other terms to the right

-18x^2^12-89x=34

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